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Saturday, August 4, 2018

Unit 2 - Velocity & Acceleration – Class 8

Velocity & Acceleration – Class 8
1.      What do you mean by reference point or origin?
-          To define state of the rest or motion of a body, a fixed point or a certain point or a considering point is required, which is known as reference point or origin.
2.      What do you mean by rest?
-          The body which is not changing its position with respect to a reference point, then the body is known as in the rest. For example: house, tree etc.
3.      What do you mean by motion?
-          The body which is changing its position with respect to a reference point, then the body is known as in the motion. For example: moving vehicle etc.
4.      Why rest and motion are called relative terms?
-          Rest and motion need comparison with a reference point to explain. So they are called relative terms.
5.      What do you mean by uniform motion?
-          If a body covers equal distance in each and every unit time, then such motion is known as uniform motion. For example: motion of needle of watch, motion of fan, motion of machines etc.
6.      What do you mean by non-uniform motion?
-          If a body doesn’t cover equal distance in each and every unit time, then such motion is known as non-uniform motion. For example: motion of a running man, bicycle etc.
7.      What do you mean by uniformly accelerated motion?
-          If velocity of a body is increasing or decreasing constantly in per unit time, then the motion is known as uniformly accelerated motion. For example: a body falling towards the center of the earth, a stone thrown vertically upward, etc.
8.      What do you mean by scalar quantity? Give examples.
-          The quantities which have only magnitude but not the direction are called scalar quantities. For example: speed, mass, length, time etc.
9.      What do you mean by vector quantity? Give example.
-          The quantities which have both magnitude and direction are called vector quantities. For example: velocity, force, displacement etc.
10.  Length is called a scalar quantity, why?
-          Because length consists only magnitude not the direction. So length is called a scalar quantity.
11.  Velocity is called as a vector quantity, why?
-          Because velocity consists both magnitude and direction. So velocity is called vector quantity.
12.  Write down the differences between vectors and scalars.
-          Following are the differences between vectors and scalars.
Scalars
Vectors
-These have magnitude only.
- These have magnitude as well as directions.
- Speed, mass, times etc. are some examples of scalars.
- Velocity, force, displacement etc. are some examples of vectors.
- These have only positive value.
- These have both positive as well as negative value.
- These can’t be added or subtracted algebraically.
- These can be added or subtracted algebraically.
13.  What do you mean by distance?
-          The length of the path travelled by a body between any two points is known as distance. It is a scalar quantity.
14.  What do you mean by displacement?
-          The shortest distance between any two points in a particular direction is known as displacement. It is a vector quantity.
15.  Write down the differences between distance and displacement.
-          Following are the differences between distance and displacement:
Distance
Displacement
-          It is the length of path joining any two points
-          It is shortest distance between any two points in particular direction.
-          It is the scalar quantity.
-          It is the vector quantity.
16.  Can displacement be zero when distance is not zero?
-          Yes. If distance is not raveled in a particular direction, then there is no displacement.
17.  Can distance is zero when displacement is not zero?
-          No. Because displacement is the distance traveled in the particular direction. So, when distance is not zero when displacement is not zero.
18.  Can distance traveled by an object be smaller than magnitude of its displacement?
-          No. Because magnitude of displacement is always less than magnitude of distance.
19.  What do you mean by speed?
-          The distance traveled by a body per unit time is known as speed. It is a scalar quantity. Its unit is m/s. Mathematically, Speed (v) = distance traveled (d)/ time taken (t)
20.  What do you mean by velocity?
-          The distance traveled by a body per unit time in a particular direction is known as velocity. It is a vector quantity. Its unit is m/s.
Mathematically, Velocity (v) = displacement (s)/time taken (t)
 (In another word, velocity is the displacement of a body per unit time.)

21.  What are the differences between speed and velocity?
-          The following are the differences between speed and velocity:
Speed
Velocity
-          It is the distance traveled by a body per unit time.
-          It is the displacement of a body per unit time.
-          It is a scalar quantity.
-          It is a vector quantity.

22.  What are the similarities between speed and velocity?
-          The unit m/s.
23.  A body has speed of 10 m/s. What does it mean?
-          It means that the body covers the distance of 10 m in each and every second.
24.  A body has velocity of 15 m/s. What does it mean?
-          It means that the body covers the distance of 15 m in each and every second in a particular direction.
25.  What is average speed?
-          The total distance traveled by a body in a certain time period is known as average speed. Mathematically, Average Speed = Total distance traveled (d)/Total time taken(t)
26.  What is average velocity?
-          The total displacement of a body in a certain time period is known as average velocity. Mathematically, Average Velocity = Total displacement (s)/Total time taken (t)
In another form, Average Velocity = (v1 + v2)/2
Similarly, Average Velocity = [initial velocity (u) + final velocity (v)] /2
27.  What is acceleration?
-         The rate of change of velocity is known as acceleration. The SI unit of acceleration is   ms-2 (meter per second square, m/s2). Similarly the negative acceleration is known as retardation. Mathematically, Acceleration (a) = [Final velocity(v) – Initial velocity(u)]/Total time taken(t)

28.  A body has an acceleration of 12ms-2, what does it mean?
-          It means that the body is increasing its velocity by 12ms-1 (m/s, meter per second) in each and every second.
29.  A body has an acceleration of 12ms-2, what does it mean?
-          It means that the body is decreasing its velocity by 12ms-1 (m/s, meter per second) in each and every second.
30.  When a body is thrown vertically upward, what is velocity at the highest point?
-          It will be zero, because there the body will stop. When a moving body stops, then its final velocity becomes zero.
31.  Can a velocity and acceleration point in opposite direction?
-          Yes, when a body is thrown vertically upward.
32.  Can speed of a body vary with its constant velocity?
-          No, it is not possible. (Because for constant velocity direction and distance per unit time should be constant. For variable speed, distance traveled per unit time and direction is not constant.)
33.  What is relative motion?
-          The motion of a body explained with respected to a reference frame is called the relative motion.
34.  What is relative velocity?
-          The velocity of a body with respect to another moving body is called as relative velocity.
35.  How relative velocity of two bodies is calculated?
-          The relative velocity is calculated by two ways:
a)      Moving in the opposite direction: the relative velocity of two bodies moving in the opposite direction is calculated by adding velocity of both bodies.
b)      Moving in the same direction: the relative velocity of two bodies moving in the same direction is calculated by subtracting velocity of one from the velocity of other bodies.
36.  What is the relative velocity of two bodies moving in the same direction with same velocity?
-          The relative velocity of two bodies moving in the same direction with same velocity is zero.
37.  What are equations of motions?
-          v = u + at, s = (u+v) x t/2 , s = ut + 1/2at2, v2 = u2 + 2as are equation of motions. These can be explained with five parameters which can be remembered as “suvat” or “utsav”.
38.  Prove v = u + at.
-          u = initial velocity
t = time taken
s = total displacement
a = acceleration
v = final velocity
as per definition, acceleration = (final velocity – Initial velocity)/time taken
                  or, a = (v-u)/t
                  or, at = v – u
                  or, v – u = at
                  or, v = at + u
                  or, v = u + at … … … (i), hence proved.
39.  Prove s = ut + 1/2at2.
u = initial velocity
t = time taken
s = total displacement
a = acceleration
v = final velocity
as per definition, acceleration = (final velocity – Initial velocity)/time taken
                  or, a = (v-u)/t
                  or, at = v – u
                  or, v – u = at
                  or, v = at + u
                        or, v = u + at … … … (i)
Similarly, total displacement = average velocity x time taken
            or, s = (u + v) x t/2
            or, s = (u + u + at) x t/2
            or, s = (2u + at) x t/2
            or, s = (2ut + at2)/2
            or, s = 2/2ut + at2/2
            or, s = ut + 1/2at2 … … …(ii), hence proved.
40.  Prove v2 = u2 + 2as.
u = initial velocity
t = time taken
s = total displacement
a = acceleration
v = final velocity
as per definition, acceleration = (final velocity – Initial velocity)/time taken
                        or, a = (v-u)/t
                        or, at = v – u
                        or, v – u = at
                        or, v = at + u
                        or, v = u + at … … … (i)
Squaring on both side of equation (i), we get,
      v2 = (u + at)2
or, v2 = u2 +2uat + a2t2
or, v2 = u2 + 2a ut + 1/2at2 2a
or, v2 = u2 + 2a(ut + 1/2at2)
or, v2 = u2 + 2as … … … (ii), hence proved.
41.  What is the acceleration of a person moving with uniform speed?
-          0 m/s2
42.  A car having mass of 1200kg is running with speed of 50m/s. The speed of the car reduced to 20m/s in 20s when driver applied brake seeing a child on the path. Calculate the retardation of the car and force applied by the driver. Also calculate the distance covered.
-          Given, initial velocity (u) = 50m/s
     final velocity (v) = 20m/s
     time taken (t) = 20s
    mass of the car (m) = 1200kg
    acceleration (a) = ?
    force (f) = ?
we know that, a = (v-u)/t
                        = (20-50)/20
                        = -30/20
                        = -1.5 m/s2
Again, as per Newton’s Second Law of Motion, F = ma
                                                                         = 1200 x 1.5
                                                                        = 1800N
Similarly, s = ut + 1/2at2
                     = 50x20 + (-1.5)x202/2
                = 1000 – 300
               = 700 m
Therefore, the retardation is 1.5m/s2, force applied is 1800N and distance covered is 700m
.
43.  A bus is travelling with a velocity of 90km/hr. On seeing school children 20m ahead on the road, the driver applies the brake and the bus stops in a distance of 1.2s. What is its retardation and mention whether the accident happens or not?
-          Given, initial velocity (u) = 90km/hr = 90x1000/60x60 = 90000/3600 = 25m/s
     final velocity (v) = 0 m/s
     time taken (t) = 1.2s
    retardation (a) = ?
    distance covered(s) = ? (dear students, we have to calculate distance covered by vehicle to know whether accident happens or not. If the distance covered by vehicle is more than the distance where the driver sees the children, i.e. 20m, accident happens, otherwise not.)
            We know that, acceleration (a) = (v-u)/t
                                                          = (0-25)/1.2
                                                          = - 2.8m/s2
            Similarly, distance covered (s) = (u+v)xt/2
                                                            = (25+0)x1.2/2
                                                            = (25x1.2)/2
                                                            =30/2
                                                            =15m(Accident doesn’t happen).
44.  A car starts from rest. It maintains an acceleration of 0.5m/s2 up to 2 km. Calculate its final velocity and time taken to cover the distance of 1.6km.
-          Given, Initial velocity (u) = 0
        Acceleration (a) = 0.5 m/s2
                Distance (s) = 1.6km = 1.6x1000 = 1600m
            Final velocity (v) = ?
            Time taken (t) = ?
We know that,         v2 = u2 + 2as
                        or, v = √(0+2x0.5x1600) = 40m/s
again,                     t = (v-u)/a

                        or, t = (40-0)/0.5 = 80s.

- GOOD LUCK -

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